Genetics for CSIR NET (Part-1)




Dear Students,
Welcome to Genetics MCQ-09 (Genetics for CSIR NET Part-1). This MCQ set consists of Advanced (PG Level) Genetics and Molecular Genetics Multiple Choice Questions taken from the previous year question papers of CSIR NET Life Sciences Examination. These questions can be used for the preparation of Competitive examinations in Biology / Life Sciences such as CSIR NET, ICMR JRF, DBT BET JRF, GATE and other University Ph.D Entrance Examinations. After marking your answers, please click ‘SUBMIT‘ button to see your ‘SCORE‘ and ‘CORRECT ANSWERS‘. 

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(1). In a heterozygous individual for a given gene, if a crossing over has occurred between the gene locus and the centromere of the chromosome, the segregation of the two alleles of the given gene will occur during meiosis at:

(a).   Either anaphase I or anaphase II
(b).   Anaphase I only
(c).   Anaphase II only
(d).  Both anaphase I and I



Ans. (c)


(2). The nodulation (nod) genes are classified as common nod genes or host specific nod genes. Some statements related to such classification are given below:

(A). nodA is a common nod gene and nodC is a host specific gene.
(B). nodB is a common nod gene and nodP is a host specific gene.
(C). nodQ is a common nod gene and nodA is a host specific gene.
(D). nodH is a common nod gene and nodQ is a host specific gene.

Choose the correct answer from the above statements:



(a).  (A) and (B)
(b). (C) and (D)
(c).  (A) only
(d). (B) only

Ans. (d)


(3). In an organism, expression of gene ‘X’ is induced in the presence of a hormone. Genetic analysis showed that the hormonal signal is transduced through two proteins Let1 and Let2. The expression of gene ‘X’ was studied in lines over-expressing (OE) the active Let proteins, knock out (KO) of the Let proteins or combination of both. Results of expression of gene ‘X’ in presence of the hormone is summarized below:

Genetics for CSIR NET



Based on the above, which one of the following pathways best fits the observation made? (CSIR_2015_II)

genetics questions csir exam(a).  Option – 1
(b). Option – 2
(c).  Option – 3
(d).  Option – 4

Ans. (b)

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(4). Two siblings who inherit 50% of the genome from the mother and 50% from the father show lot of phenotypic differences. Which one of the following events during gametogenesis of the parents will maximally contribute to this difference?

(a).  Mutation
(b). Recombination
(c).  Independent assortment
(d). Environment



Ans. (c)





(5). Consider the following hypothetical pathway:

H allele converts X substance to H substance
h allele cannot convert X to H substance and leads to phenotype ‘O’
A allele converts H substance leading to A phenotype
a allele cannot convert H substance
B allele converts H substance leading to B phenotype
b allele cannot convert H substance

An individual with A phenotype when crossed with that of B phenotype has a progeny with O phenotype. Which one of the following crosses can lead to the above observation?




(a).  Aahh X  BbHH
(b). AaHh  X BBHh
(c).  AaHh  X BBHH
(d). AAHH  X BbHh

Ans. (b)


(6). Three somatic hybrid cell lines, designated as X, Y and Z, have been scored for the presence or absence of chromosomes 1 through 8, as well as for their ability to produce the hypothetical gene product A, B, C and D as shown in the following table:

Which of the following option has most appropriately assigned chromosomes for each of the given genes?




(a).  Gene A on chromosome 5, Gene B on chromosome 3, Gene C on chromosome 8 and Gene D on chromosome 1
(b). Gene A on chromosome 5 and Gene B on chromosome 3 only
(c).  Gene D on chromosome 8, Gene C on chromosome 1, Gene B on chromosome 5 and Gene A on chromosome 4
(d). Gene A on chromosome 5, Gene B on chromosome 3 and Gene D on chromosome 1

Ans. (d)


(7). In a linkage map, two genes A and B, are 70 cM apart. If individuals heterozygous for both the genes are test crossed number of progeny with parental phenotype will be:

(a).  Equal to the number of progeny with recombinant phenotype
(b). More than the number of progeny with recombinant phenotype
(c).  Less than the number of progeny with recombinant phenotype
(d). Could be more or less than the number of progeny with recombinant phenotype depending on whether the genes are linked in cis or trans, respectively

Ans. (a)





(8). A researcher exposed Drosophila larvae to 37⁰C during their growth. One of the adult flies that emerged had a crossveinless phenotype. Crossveinless is a known mutant in Drosophila. When this crossveinless fly was crossed to a known crossveinless mutant fly all the progeny had normal phenotype. The observed phenotype can be best explained as an example of:

(a).  Conditional mutant
(b). Phenocopy
(c).  Penetrance
(d). Pleiotropy

Ans. (b)




 


(9). Phages are collected from an infected E. coli donor strain of genotype cys+ leu+ thr+ and used to transduce a recipient of genotype cys- leu- thr-. The treated recipient population is plated on a minimal medium supplemented with leucine and threonine. Many colonies grew. Which one of the following combination of genotypes are appropriate for the colonies that grew?

(a).  cys+ leu+ thr+ ; cys+ leu- thr+ ; cys- leu+ thr-
(b). cys- leu – thr+ ; cys+ leu- thr- ; cys+ leu+ thr-
(c).  cys- leu- thr- ; cys-leu- thr+ ; cys- leu+ thr-
(d).  cys+ leu- thr- ; cys+ leu- thr+ ; cys+ leu+ thr-

Ans. (d)


(10). The inheritance of a given disorder is recorded in three small families shown below:

Based on the above limited information, which one of the following inheritance pattern best explains the observations?
(a).  X-linked recessive
(b). X-linked dominant
(c).  Autosomal recessive
(d). Autosomal dominant

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