DBT BET JRF – 2014 Biotechnology JRF Solved Question Paper (PDF)
Original / Official Solved Question Paper of DBT BET JRF Examination 2014 with Answer Key (Department of Biotechnology – Biotechnology Eligibility Test – Junior Research Fellowship). You can download this question paper as PDF file for the preparation of your examination. The answer key is prepared with the official answer key. Please inform the Admin if you find any mistake in the answer key. To download the question paper, please click on the Download Icon available in the upper right corner of the PDF preview. You can also save the file to your computer by ‘Right-Click’ anywhere on the PDF preview and selecting ‘Save-as‘ from the pop-up menu.
Biotechnology Eligibility Test (BET) for DBT JRF Award (2012-13) Previous Year Question Papers with Answer Key, Explanations & References Government of India, Ministry of Science & Technology Department of Biotechnology, New Delhi PART: B Set 4 (Questions 101– 150)
101. Telomeres consists of simple sequence repeats of
a. CATT rich strands that interact with protein b. GCCT rich strands that interact with protein c. CTTT rich strands that interact with protein d. TTAGGG rich strands that interact with protein
Ans. (a)
Telomere is the sequence occurs at the end of chromosome. Telomere helps to maintain the integrity of chromosome by preventing the end to end fusion of different chromosome and deterioration of chromosomes by nucleases. In vertebrates telomere consists of TTAGGG sequence repeats (~2500 repeats).
102. True activators of transcription are transcription factors that binds to
a. Other proteins to enhance transcription b. Promoters c. Enhancers d. Promoters and enhancers
Ans. (c)
Enhancers are cis acting transcription factor binding sites of DNA (50 – 1500 bp long) of specific genes
Biotechnology Eligibility Test (BET) for DBT JRF Award (2012-13) Previous Year Question Papers with Answer Key, Explanations & References Government of India, Ministry of Science & Technology Department of Biotechnology, New Delhi
PART: B Set 3 (Questions 51 – 100)
51. Suppressor tRNA mutations are those in which
a. Transcription of tRNA genes is suppressed b. Translation form mRNA is suppressed due to absence of tRNA c. Amino acid is incorporated in place of a stop codon due to mutation in anticodon region of tRNA d. Charging of tRNA with cognate amino acids is suppressed due to mutation in amino acyl tRNA synthase enzyme
Ans. (c)
Suppressor tRNA: also called as nonsense suppressor, due to the suppressor tRNA mutations, an amino acid is incorporated into the stop codon due to mutation in the anticodons of tRNA so that the releasing factors of translation cannot binds to the complex and the translocation process continues.
52. Which of the following media is best suited for the selective growth of E. coli with genotype: Str+ His- leu- lys-?
a. Minimal medium with thiamine, histidine, leucine and lysine b. Luria agar c. Minimal medium with thiamine and streptomycin d. Minimal medium with thiamine, histidine, leucine, lysine and streptomycin
Ans. (d)
Minimal medium: media that contains minimum nutrients possible for bacterial growth, usually without the presence of amino acids. They used by microbiologists and geneticists to grow “wild type” microorganisms and to select microbes against recombinants.
In the question, the given bacterium is mutated for Histidine, Leucine, and lysine and it has got an antibiotic resistant gene Str+.
53. Which of the following amino acid is coded by maximum number of codons?
Biotechnology Eligibility Test (BET) for DBT JRF Award (2012-13) Previous Year Question Papers with Answer Key, Explanations & References Government of India, Ministry of Science & Technology Department of Biotechnology, New Delhi
PART: A Set 2 (Questions 26 – 50)
26. Which one of the following is the natural host for pseudo-rabies virus?
a. Dog b. Man c. Swine d. Horse
Ans. (c). Swine
Pseudorabies (Aujeszky’s disease) is a viral disease of swine caused by Suid herpesvirus 1 (SuHV1) belongs to the family Herpesviridae. Other species such as sheep, cattle, and human are also susceptible to SuHV1. This disease is nothing to do with rabies virus. The notorious Rabies virus belongs to the family Rhabdoviridae which cause rabies in human and animals.
27. Which one of the following is the causative agent of fowl cholera?
a. V. cholera b. P. multocida c. E. coli d. S. pullorum
Ans. (b). P. multicida
Fowl cholera or avian cholera is caused by Pasteurella multocida. Fowl cholera is considered as Zoonoses
Zoonoses: an infectious disease of animals that can be transferred to human, Example: Rabies
S. pullorum is a poultry adapted species of Salmonella
28. The wavelengths of light that penetrate the least into the ocean are
a. Red and violet b. Red and yellow c. Blue and brown d. Green and blue
Ans. (b). Red and Yellow
Yellow, orange and red waves have the least energy in the visible spectrum, thus they cannot penetrated deep into the sea. This is the reason why most of the deep sea animals (fishes) are red in colour. In the deep sea, due to absence of enough light the red colour appears as black so that these animals can be escaped from their predators.
Biotechnology Eligibility Test (BET) for DBT JRF Award (2012-13) Previous Year Question Papers with Answer Key, Explanations & References Government of India, Ministry of Science & Technology Department of Biotechnology, New Delhi
PART: A Set 1 (Questions 001 – 025)
1. The immunoglobulin fold is made up of:
a. Seven alpha helical segments b. A beta barrel c. A sandwich of two parallel beta sheets d. A sandwich of two antiparallel beta sheets
Ans. (d). A sandwich of two antiparallel beta sheets
Immunoglobulin fold consists of a pair of β-sheets each built of antiparallel β-strands connected by a disulfide bridge. This β strands surrounds a central hydrophobic core. Immunoglobulin fold is one of the most predominant domains encoded by the human genome.
For more details refer: Biochemistry by Stryer, Ed.6, Chapter: 33, Immune systems, Page 951
2. RNA is analyzed for the location of hairpin folds. Which of the following sequence could form a mini-hairpin?
a. AGGUUUCCU b. AAAAAAAAA c. AGGUUUGGA d. AGGUUUAGG
Ans. (a). AGGUUUCCU
This RNA molecule can loop around itself and can form double stranded structure due to the sequence complementarity. First A is complementary to last U, second and third nucleotide (UU) is complementary to CC. The middle UUU forms the junction of loop and they do not form the complementary hydrogen bonds.
3. Increasing the concentration of which of the following would most effectively anatomized the inhibition of protein synthesis by puromycin?
a. ATP b. eIF2, GTP c. Aminoacyl-tRNAs d. Peptidyl-tRNAs
Ans. (c). Aminoacyl-tRNA
Puromycin is an antibiotic obtained from a bacterium Streptomyces alboniger, which inhibit protein synthesis by specifically inhibiting the translation process. Puromycin inhibits protein translation by premature chain termination process. A part of the puromycin structurally mimics the 3’ end of Aminoacyl-tRNA molecule and hence they can enter to the ‘A’ site of ribosome and form a nascent peptide-puromycin adduct. This adducts formation results in the release of peptide from the ribosome. Puromycin compete with aminoacyl-tRNA for the A site of ribosome. Thus the inhibitory effect of puromycin can be theoretically overcome by increasing the concentration of the competitor, i.e., aminoacyl-tRNA.
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