Life Sciences JRF NET Dec. 2018 Model Question Paper (Mock Test 25) NET Life Sciences Old Papers NET Life Sciences Mock Test Welcome to Life Sciences CSIR Mock Test 25 This Mock Test consists of 15 questions in MCQ format. At the end of the mock test, you have to click on the 'SUBMIT' button to see your Score and the Correct Answers. 1. A polysome can be described as Involved in control of transcription in prokaryotes A special ribosome occurring in prokaryotes A DNA strand which is being transcribed by may RNA polymerase String of RNA occupied by many ribosomes2. Secretion of histamine by degranulation from which cell leads to immediate hypersensitivity T-helper cells B-cells Mast cells Basophils3. If there is no correct initiation of transcription, which subunit of RNA polymerase holo-enzyme would have defect? β’ subunit α subunit β subunit σ subunit4. Which species concept stress mainly on failure of interbreeding to keep them in distinct species? Ecological species concept Morphological species concept Phylogenetic species concept Biological species concept5. In mitochondrial succinyl CoA synthetase produces ATP AMP ADP GTP6. Recently reptile fossils of age 200-250 MY have been found in Brazil and Ghana portion of West Africa. The landmass during that period was a portion of: Pangea Laurasia Tethys Sea Gondwana7. The pattern of genomic imprinting is maintained from one generation to another by Methylation of DNA Phosphorylation of DNA Glycosylation Acetylation8. The cells of warm-blooded animals can be best stored at temperatures 0°C -196°C 37°C -100°C 9. Among the following which gene is not concerned with the induction of cancer? Tubulin P53 Ras Src10. Among the following, the Mendelian inheritance is obeyed by: Organelles Gene for vertical transfer of disease Transposons Quantitative traits11. The morphologically distinct sexual dimorphism is absent in: Hyena, bulbul, Sparrow Crow, peacock, bulbul Myena, bulbul, Koel Peacock, Myena, bulbul12. Among the following which compound links glycolysis and Kreb’s cycle Glucose Acetyl CoA Oxaloacetic acid Pyruvic Acid13. If an enzyme obeying Hills reaction shows negative co-operativity. It means: Binding of substrate to any one site of multi-subunit enzyme makes enzyme non-functional Binding of substrate to any one site of single unit enzyme decreases affinity for other substrate Binding of substrate to any one site of multisubunit enzyme decreases affinity for other substrate to other sub-units Binding of substrate to any one site of multi-subunit enzyme increases affinity for other substrate to other sub-units14. Which cell is involved in eliminating the antigen non-specifically by engulfing them? Killer T-cells T-helper cells Phagocytotic cells B-cells15. Suppose a parasitic bacterium prevent cross breeding in an insect pollution, it will lead to: Divergence of insects No effect Extinction of insects Rapid speciationYou have reached at the End of this Mock Test. Please Click 'SUBMIT' button to see your Score and the Correct Answers... More Online Mock Tests… Please follow the links below… CSIR JRF NETICMR JRFDBT BET JRFGATE - BTGATE XL Bioche.GATE XL Micro.GATE XL BotanyGATE XL ZoologyGATE XL Food Tec.GATE EY EcologyIIT JAM - BTIIT JAM - BLGS - BiologySET - BotanySET - ZoologyNEET Get our Updates on CSIR NET Life Sciences in your E-mail Inbox We will not spam your account… Enter your e-mail address Don’t forget to Activate your Subscription…. Please See Your E-Mail… Browse more in Easy Biology Class… Lecture NotesBiology PPTVideo TutorialsBiology MCQQuestion BankDifference betweenPractical AidsMock Tests (MCQ)Biology Exams If you like this post, Please COMMENT . . . . (below ↓) Please Share with your Friends, Relatives, Students and Colleagues… No related posts. Posted in CSIR / ICMR / DBT / ICAR, CSIR NET Mock Test, CSIR NET Model Questions, Mock (Practice) Tests and tagged CSIR JRF NET Dec 2018, NET Life Sciences Mock Test, NET Life Sciences Model Questions, NET Life Sciences Practice Questions.