CSIR JRF NET Life Sciences Mock Test 04 (Free Online Practice Questions) CSIR JRF NET Life Sciences Mock Test 04 Welcome to CSIR JRF NET Life Sciences Mock Test (CSIR Mock Test 04) This Mock Test consists of 15 questions in MCQ format. At the end of the mock test, you have to click on the 'SUBMIT' button to see your Score and the Correct Answers. Please click on the 'NEXT' button to Start the Mock Test... 1) Which is the correct explanation for sibling species? Species which are morphologically different but can interbreed Species which are morphologically alike and can interbreed Species which are morphologically different and reproductively isolated Species which look morphologically similar but reproductively isolated2) Anterior‐posterior limb axis and dorsal ventral nerve plate is determined by Sonic hedgehog Bicoid Pax3 Cactus3) Which portion of antibodies is recognized by Fc receptor of macrophages? Heavy chain λ‐Chain J‐ chain κ‐ Chain4) In prokaryotes, the IF2 binds to: Ribosome and m‐RNA Amino acyl t‐RNA and ATP Initiator t‐RNA and GTP m‐RNA and 30S subunit of ribosome5) In prokaryotes, which subunit of RNA polymerase is released after the initiation process? α β σ β’ 6) Uricotelism is an adaptation for: Marine habitats High altitudes Conserving water Conserving salt7) Which statement is NOT correct regarding Brown Fat? It produces more heat It is present in lesser amount in new born baby It produces little ATP Uncoupled phosphorylation8) Major function of lymphatic system is: Phagocytosis Innate immunity Maintain fluid balance Acquired immunity9) Hypertrophy in the anterior pituitary in adults leads to: Cretinism Gigantism Dwarfism Acromegaly10) For the final processing of antigen, the macrophages after phagocytosis directs engulfed material to: Peroxisome Proteasome ER Lysosome11) Which is NOT a strategy for the adaptation to dry environment? High root to shoot ratio Low stomatal conductance C4/CAM Cycle Thick cuticle12) Aggregation of myxamoebae into slime mould during the formation of fruiting bodies is an example of: Social behavior Pattern formation Multi-cellularity Embryonic development13) If we compare the convoluted tubule and the ascending limb of Henle of nephron. The fluid is Isotonic and hypotonic Dilute and isotonic Dilute and hypotonic Isotonic and hypertonic14) In coli, gal+ and bio+ genes are located very near to each other on the genome. A bacterium with F’ gal+ on conjugation with F‐ will lead to diploid condition for E. coli will always remain haploid gal and bio bio only gal only15) On the basis of statements given below, the mode of inheritance is: Mostly male shows the disease All male child developed from an affected mother are diseased Female develop disease only when her father is diseased and mother is a carrier Autosomal dominant X-linked dominant X-linked recessive Autosomal recessiveYou have reached at the End of this Mock Test. Please Click 'SUBMIT' button to see your Score and the Correct Answers... More Online Mock Tests… Please follow the links below… CSIR JRF NETICMR JRFDBT BET JRFGATE - BTGATE XL Bioche.GATE XL Micro.GATE XL BotanyGATE XL ZoologyGATE XL Food Tec.GATE EY EcologyIIT JAM - BTIIT JAM - BLGS - BiologySET - BotanySET - ZoologyNEET Get our Updates on CSIR NET Life Sciences in your E-mail Inbox We will not spam your account… Enter your e-mail address Don’t forget to Activate your Subscription…. Please See Your E-Mail… Browse more in Easy Biology Class… Lecture NotesBiology PPTVideo TutorialsBiology MCQQuestion BankDifference betweenPractical AidsMock Tests (MCQ)Biology Exams If you like this post, Please COMMENT . . . . (below ↓) Please Share with your Friends, Relatives, Students and Colleagues… No related posts. Posted in CSIR / ICMR / DBT / ICAR, CSIR NET Mock Test, CSIR NET Model Questions, Mock (Practice) Tests and tagged CSIR JRF NET Life Sciences, Life Science JRF Mock Test, NET Life Sciences Mock Test, NET Life Sciences Practice Questions, Online Mock Test.